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Newton's First Law (Translational Equilibrium)

AP Physics 1· difficulty 2/5

A 20 N20~\text{N} box rests on a floor with μs=0.40\mu_s = 0.40. A horizontal push of 5 N5~\text{N} is applied but the box doesn't move. What is the static friction on the box?

  • A

    8 N8~\text{N}

  • B

    5 N5~\text{N}

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  • C

    0 N0~\text{N}

  • D

    20 N20~\text{N}

Explanation

Static friction matches the applied force up to its maximum (μsN=0.40×20=8 N\mu_s N = 0.40 \times 20 = 8~\text{N}). Here applied is only 5 N5~\text{N}, so fs=5 Nf_s = 5~\text{N}.

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