Pressure

AP Physics 1· difficulty 2/5

A small hole in a large open tank is at depth 0.80 m0.80~\text{m} below the surface. Water exits at speed (using g10 m/s2g \approx 10~\text{m/s}^2):

  • A

    4.0 m/s4.0~\text{m/s}

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  • B

    1.0 m/s1.0~\text{m/s}

  • C

    2.0 m/s2.0~\text{m/s}

  • D

    8.0 m/s8.0~\text{m/s}

Explanation

v=2gh=16=4.0 m/sv = \sqrt{2gh} = \sqrt{16} = 4.0~\text{m/s}.

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