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Fluids and Newton's Laws (Buoyancy)

AP Physics 1· difficulty 3/5

A 2.0 kg2.0~\text{kg} object is fully submerged in water and hangs from a spring scale. If its volume is 5.0×10−4 m35.0 \times 10^{-4}~\text{m}^3, what does the scale read? (g≈10 m/s2g \approx 10~\text{m/s}^2, ρw=1000 kg/m3\rho_w = 1000~\text{kg/m}^3.)

  • A

    25 N25~\text{N}

  • B

    5 N5~\text{N}

  • C

    15 N15~\text{N}

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  • D

    20 N20~\text{N}

Explanation

Weight: mg=20 Nm g = 20~\text{N}. Buoyancy: FB=ρwgV=(1000)(10)(5.0×10−4)=5.0 NF_B = \rho_w g V = (1000)(10)(5.0 \times 10^{-4}) = 5.0~\text{N}. Scale reads 20−5=15 N20 - 5 = 15~\text{N}.

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