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Fluids and Newton's Laws (Buoyancy)

AP Physics 1· difficulty 3/5

A 1 kg1~\text{kg} object of volume 5×10−4 m35 \times 10^{-4}~\text{m}^3 hangs submerged in oil (ρ=800 kg/m3\rho = 800~\text{kg/m}^3, g≈10 m/s2g \approx 10~\text{m/s}^2). Spring scale reading?

  • A

    6 N6~\text{N}

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  • B

    2 N2~\text{N}

  • C

    8 N8~\text{N}

  • D

    4 N4~\text{N}

Explanation

Weight: 10 N10~\text{N}. Buoyancy: (800)(10)(5×10−4)=4 N(800)(10)(5 \times 10^{-4}) = 4~\text{N}. Scale: 10−4=6 N10 - 4 = 6~\text{N}.

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