Glucose, fructose, and galactose share what general formula?

Answer: C₆H₁₂O₆ They are isomers — same molecular formula C₆H₁₂O₆, different structures.

Which of the following is <strongnot</strong one of the four major classes of biological macromolecules?

Answer: Minerals The four classes are carbohydrates, lipids, proteins, and nucleic acids. Minerals are inorganic.

Which solution most likely contains glucose?

Answer: A Benedict's reagent detects reducing sugars (free aldehyde or ketone groups). Glucose is a reducing sugar; the red precipitate from Benedict's is a positive test. A is the glucose solution.

AP Biology · Topic 1.3

Introduction to Biological Macromolecules Practice

Q: Which of the following is <strongnot</strong one of the four major classes of biological macromolecules?

Answer: Minerals The four classes are carbohydrates, lipids, proteins, and nucleic acids. Minerals are inorganic.

Q: Which solution most likely contains glucose?

Answer: A Benedict's reagent detects reducing sugars (free aldehyde or ketone groups). Glucose is a reducing sugar; the red precipitate from Benedict's is a positive test. A is the glucose solution.

Part of Chemistry of Life.(SYI-1.C)

Practice questions

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Sample questions

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Sample 1difficulty 1/5
$Glucose, fructose, and galactose share what general formula?$
- A
  $C₆H₆O₂$
- B
  $C₅H₁₀O₅$
- C
  $C₆H₁₂O₆$
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- D
  $C₁₂H₂₂O₁₁$
Why
$They are isomers — same molecular formula C₆H₁₂O₆, different structures.$
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Sample 2difficulty 1/5
$Which of the following is <strong> not </strong> one of the four major classes of biological macromolecules?$
- A
  $Lipids$
- B
  $Carbohydrates$
- C
  $Nucleic acids$
- D
  $Minerals$
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Why
$The four classes are carbohydrates, lipids, proteins, and nucleic acids. Minerals are inorganic.$
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Sample 3difficulty 2/5
$A student tests four unknown solutions (A, B, C, D) for the presence of biological macromolecules using four indicators: Benedict's (reducing sugars - color change to red/orange when boiled), iodine (starch - black-blue), biuret (protein - violet), and Sudan IV (lipid - red). Results: A turns red with Benedict's; B turns blue-black with iodine; C turns violet with biuret; D turns red with Sudan IV.$
$Which solution most likely contains glucose?$
- A
  $C$
- B
  $D$
- C
  $B$
- D
  $A$
  check_circle
Why
$Benedict's reagent detects reducing sugars (free aldehyde or ketone groups). Glucose is a reducing sugar; the red precipitate from Benedict's is a positive test. A is the glucose solution.$
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Sample 4difficulty 2/5
$Saturated fats differ from unsaturated fats because they$
- A
  $Have an extra hydroxyl group on each fatty-acid tail$
- B
  $Have no double bonds in their fatty-acid tails$
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- C
  $Have shorter glycerol backbones than unsaturated fats$
- D
  $Have one cis double bond in their fatty-acid tails$
Why
$Saturated = no C=C double bonds in the tails (each C is "saturated" with H). The tails pack tightly, making saturated fats more solid at room temperature.$
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Sample 5difficulty 3/5
$The student tests an unknown E and finds it gives a positive test with both Benedict's reagent and biuret reagent.$
$What is the most likely composition of E?$
- A
  $Pure starch$
- B
  $A mixture containing both reducing sugar and protein$
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- C
  $Pure water$
- D
  $A lipid emulsion$
Why
$Two positive tests indicate the presence of two macromolecule types. Benedict + biuret = reducing sugar + protein. The most likely composition of E is a mixture of both classes.$
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