AP Physics 1 · Topic 5.4

Rotational Inertia Practice

Part of Torque and Rotational Dynamics.(TOP-5.D)

Practice questions

3

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Sample questions

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  1. Sample 1difficulty 2/5

    Of the following objects (all same mass MM and radius RR), which has the <strong>largest</strong> moment of inertia about its symmetry axis?

    • A

      Thin hoop / ring: MR2MR^2

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    • B

      Solid disk/cylinder: 12MR2\frac{1}{2}MR^2

    • C

      Solid sphere: 25MR2\frac{2}{5}MR^2

    • D

      Thin rod about its center, length RR: 112MR2\frac{1}{12}MR^2

    Why

    The hoop concentrates all mass at the maximum distance from the axis, giving the largest I=MR2I = MR^2.

  2. Sample 2difficulty 4/5

    axis CM L, M

    A thin uniform rod of mass MM and length LL has moment of inertia 112ML2\tfrac{1}{12}ML^2 about its center. What is its moment of inertia about an axis perpendicular to the rod through one end?

    • A

      ML2ML^2

    • B

      13ML2\tfrac{1}{3}ML^2

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    • C

      112ML2\tfrac{1}{12}ML^2

    • D

      16ML2\tfrac{1}{6}ML^2

    Why

    Parallel-axis: I=Icm+Md2=112ML2+M(L/2)2=13ML2I = I_{cm} + Md^2 = \tfrac{1}{12}ML^2 + M(L/2)^2 = \tfrac{1}{3}ML^2.

  3. Sample 3difficulty 4/5

    A solid disk and a hoop of equal mass and radius roll down identical inclines from rest. Which reaches the bottom first?

    • A

      Depends on incline angle

    • B

      Hoop

    • C

      Same

    • D

      Disk (smaller I/MR2I/MR^2 → less rotational KE → more translational KE → faster)

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    Why

    Disk I=12MR2I = \frac{1}{2}MR^2; hoop I=MR2I = MR^2. The disk converts more PE to translational KE (less to rotation), so it accelerates faster.