Question

How do you describe the end behavior of common functions?

Original question: 6. (a) Briefly describe the behaviour of the $y$ values for each of the following graphs, given the behaviour of the $x$ values. (i) $y=x^4$ as $x\to\infty$. (ii) $y=(2-x)^3$, as $x\to\infty$. (iii) $y=\frac{1}{x}$ as $x\to-\infty$.

Expert Verified Solution

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Expert intro: End behavior questions test whether you can read a graph or formula without overthinking it. The key is to track what happens to the output when the input becomes very large.

Detailed walkthrough

We describe each function in turn.

(i) y=x4y=x^4 as xx\to\infty

As xx gets larger and larger, x4x^4 also gets larger and larger.

So

y.y\to\infty.

(ii) y=(2x)3y=(2-x)^3 as xx\to\infty

When xx becomes very large, 2x2-x becomes very large and negative. A negative number cubed stays negative and grows in magnitude.

So

y.y\to-\infty.

(iii) y=1xy=\frac{1}{x} as xx\to-\infty

As xx becomes a very large negative number, the reciprocal gets closer to zero.

So

y0.y\to 0.

If you want to be extra precise, it approaches 00 from below.

💡 Pitfall guide

Do not confuse the sign inside (2x)3(2-x)^3. For large xx, the expression is not positive just because it is cubed. The inner term 2x2-x is negative.

Also, for 1x\frac{1}{x}, do not say the output becomes very large in magnitude. It actually shrinks toward zero.

🔄 Real-world variant

If part (ii) were y=(2x)4y=(2-x)^4 instead, then the output would go to ++\infty because an even power removes the negative sign. If part (iii) were y=1x2y=\frac{1}{x^2} as xx\to-\infty, the result would still be 00, but from the positive side.

🔍 Related terms

end behavior, power function, reciprocal graph

FAQ

What is the end behavior of $y=x^4$ as $x\to\infty$?

The values of $y$ increase without bound, so $y\to\infty$.

What happens to $y=(2-x)^3$ as $x\to\infty$?

Since $2-x$ becomes very negative, cubing it gives values that decrease without bound, so $y\to-\infty$.

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