Question

Graphing a circle and a parabola, then checking which one is a function

Original question: 9. (10 marks) Chapter 1: Functions and Graphs 1.2.4, 1.2.6, 1.2.17, 1.2.18, 1.2.24 (2022-522:OF) (a) On the axes below, sketch the graphs of the following two relations. (3 marks) $x^2+y^2=9$ $y=x^2+4$ One of the relations in part (a) is also a function. (b) Identify which relation is a function, explaining how you made your choice. (2 marks) The student says the minimum distance between the two graphs is 1 unit. (c) Using your graph in part (a), explain why the student is correct. (1 mark) The student is investigating other parabolic graphs where the minimum distance between the parabola and $x^2+y^2=9$ is 1 unit. (d) State a equation of another parabola that has the same line of symmetry as $y=x^2+4$, and is concave down. (2 marks) CONTINUED NEXT PAGE

Expert Verified Solution

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Expert intro: This question mixes graphing, the vertical line test, and a little geometric reasoning. The student’s comment about distance is not something you guess; it has to be visible from the shape of the graphs.

Detailed walkthrough

(a) Sketch the two relations

  1. x2+y2=9x^2+y^2=9

    • This is a circle centered at the origin.
    • Radius: 9=3\sqrt{9}=3.
    • It crosses the axes at (±3,0)(\pm 3,0) and (0,±3)(0,\pm 3).
  2. y=x2+4y=x^2+4

    • This is a parabola opening upward.
    • Vertex: (0,4)(0,4).
    • Axis of symmetry: the yy-axis.

(b) Which relation is a function?

The relation y=x2+4y=x^2+4 is a function because each xx value gives exactly one yy value.

The circle x2+y2=9x^2+y^2=9 is not a function of xx because many vertical lines hit it twice. For example, when x=0x=0, the equation gives y=±3y=\pm 3.

(c) Why is the minimum distance 1 unit?

Look at the top of the circle and the bottom of the parabola:

  • Highest point on the circle: (0,3)(0,3)
  • Lowest point on the parabola: (0,4)(0,4)

These points lie on the same vertical line, so the distance between them is

43=1.4-3=1.

Since the parabola stays above the circle near that region, this is the minimum distance.

(d) Another parabola with the same axis of symmetry and concave down

A parabola with the same line of symmetry as y=x2+4y=x^2+4 must have axis x=0x=0. To make it concave down, the coefficient of x2x^2 must be negative. One valid example is

y=x2+4.y=-x^2+4.

💡 Pitfall guide

A common mistake is to say the circle is a function because it has a neat formula. The vertical line test is the real check. Another trap is thinking the minimum distance must come from the nearest-looking edges; here, the vertical gap between (0,3)(0,3) and (0,4)(0,4) is the one that matters.

🔄 Real-world variant

If the parabola were shifted, say y=x2+5y=x^2+5, then the minimum distance to the circle would become 2 units instead of 1, because the lowest point of the parabola would be at (0,5)(0,5). If the parabola opened downward but kept the same axis, any equation of the form y=ax2+ky=-ax^2+k with a>0a>0 would work.

🔍 Related terms

vertical line test, axis of symmetry, minimum distance

FAQ

Which graph is a function, the circle or the parabola?

The parabola y = x^2 + 4 is a function because each x-value gives exactly one y-value. The circle x^2 + y^2 = 9 is not a function of x because some vertical lines intersect it twice.

Why is the minimum distance between the graphs 1 unit?

The top of the circle is at (0,3) and the bottom of the parabola is at (0,4). These points are one unit apart vertically, so the minimum distance is 1.

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