Question

Find the step where the circle-equation work goes wrong

Original question: 6. Kevin's work for deriving the equation of a circle is shown below. EXPLAIN YOUR ANSWER.

x^2 + 4x = -y^2 + 20 STEP 1 x^2 + 4x = -y^2 + 20 STEP 2 x^2 + 4x = y^2 + 20 STEP 3 (x + 2)^2 = y^2 + 20 - 4 STEP 4 (x + 2)^2 - y^2 = 16

In which step did he make an error in his work?

  1. Step 1
  2. Step 2
  3. Step 3
  4. Step 4

Expert Verified Solution

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Key concept: When a circle equation is being rewritten, the safest move is to check each transformation line by line. One sign error can change the whole result, even if later steps look neat.

Step by step

Start with the given equation:

x2+4x=y2+20x^2 + 4x = -y^2 + 20

Now compare Kevin’s steps.

Step 1

He rewrites the equation exactly as given:

x2+4x=y2+20x^2 + 4x = -y^2 + 20

That part is fine.

Step 2

He changes it to

x2+4x=y2+20x^2 + 4x = y^2 + 20

This is the mistake. The term y2-y^2 should not become y2y^2 unless you multiply the entire equation by 1-1 or move the term properly with opposite sign. He changed only one side’s sign incorrectly.

Quick check

If you wanted to move y2-y^2 to the left side, you would add y2y^2 to both sides:

x2+4x+y2=20x^2 + 4x + y^2 = 20

That is not what Kevin wrote.

Therefore

The first error happens in Step 2.

Correct choice: 2) Step 2

Pitfall alert

A common trap is to trust the later perfect-looking square completion and ignore the earlier sign change. In algebra, one wrong sign can still lead to a clean-looking but false final form. Always check whether the same operation was applied to both sides.

Try different conditions

If Kevin had instead written

x2+4x+y2=20,x^2+4x+y^2=20,

then he could complete the square on xx:

(x+2)24+y2=20(x+2)^2-4+y^2=20

which becomes

(x+2)2+y2=24.(x+2)^2+y^2=24.

That would describe a circle with center (2,0)(-2,0) and radius 24=26\sqrt{24}=2\sqrt{6}.

Further reading

circle equation, completing the square, sign error

FAQ

In which step did Kevin make the first error?

The first error is in Step 2. The term -y^2 was changed to y^2 incorrectly; that sign change is not valid unless the whole equation is handled consistently.

Why is Step 1 correct?

Step 1 simply restates the original equation without changing anything, so it is correct.

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