Question
What is the general form of a first-order ordinary differential equation?
Original question: First order ordinary differential equations general form : $y'(x)=F(x,y)$ , here $y$ is a function of $x$ $F$ is a function of two variables
Expert Verified Solution
Key concept: A first-order differential equation is one of the first places where notation matters. Once the roles of the variables are clear, the definition becomes straightforward.
Step by step
A first-order ordinary differential equation (ODE) is an equation involving:
- an unknown function, usually written as ,
- its first derivative ,
- and often the independent variable itself.
A common general form is
Here:
- is the independent variable,
- is the dependent variable, meaning ,
- is some function of the two variables.
Sometimes the same idea is written as
Both forms mean the same thing.
If the equation can be written as only, then it is still first-order, just a simpler special case.
Pitfall alert
It is easy to think must be a function of only or only , but in the general case it can depend on both.
Also, the order is determined by the highest derivative present. If only appears, it is first-order; if appears, it is second-order.
Try different conditions
If the equation is written implicitly, such as
it may still be a first-order ODE after dividing by when possible:
So the same first-order idea can appear in several notations.
Further reading
ordinary differential equation, dependent variable, first derivative
FAQ
What is the general form of a first-order ODE?
A common general form is y'(x)=F(x,y), where y is a function of x and F depends on x and y.
What makes an equation first-order?
An equation is first-order if the highest derivative that appears is the first derivative, such as dy/dx or y'.