Question

C_U (M \cap N)

Original question: Given the universal set U = {1, 2, 3, 4, 5, 6, 7, 8}, M = {3, 4, 5, 6}, N = {4, 5, 6, 7},

then C_U (M \cap N) = ?

(Here, C_U means the complement of the set M \cap N in the universal set U.)

Options: A. {2, 8} B. {4, 5, 6} C. {2, 3, 7, 8} D. {3, 4, 5, 6, 7}

Expert Verified Solution

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Key takeaway: This question uses the complement of an intersection inside a universal set. The key is to find the common elements of MM and NN, then list everything in UU that is not in that overlap.

Step 1: Find the intersection

Given:

  • U={1,2,3,4,5,6,7,8}U = \{1,2,3,4,5,6,7,8\}
  • M={3,4,5,6}M = \{3,4,5,6\}
  • N={4,5,6,7}N = \{4,5,6,7\}

The intersection is the set of elements common to both MM and NN:

MN={4,5,6}M \cap N = \{4,5,6\}

Step 2: Take the complement in UU

The complement of MNM \cap N in UU is everything in UU except {4,5,6}\{4,5,6\}:

CU(MN)={1,2,3,7,8}C_U(M \cap N) = \{1,2,3,7,8\}

Step 3: Match with the options

The correct complement is:

  • {1,2,3,7,8}\{1,2,3,7,8\}

If the options are exactly as written, none of the listed choices matches this result. The set corresponding to the correct computation is {1,2,3,7,8}\{1,2,3,7,8\}.


Pitfalls the pros know 👇 A common mistake is to complement MM and NN first and then intersect them, which gives a different result. Here the complement is taken after finding MNM \cap N.

Also, be careful not to exclude the wrong elements from the universal set UU. Only 4,5,64,5,6 belong to the intersection, so only those three should be removed.

What if the problem changes? If the question had asked for CU(MN)C_U(M \cup N) instead, you would first compute

MN={3,4,5,6,7}M \cup N = \{3,4,5,6,7\}

and then take the complement in UU:

CU(MN)={1,2,8}C_U(M \cup N) = \{1,2,8\}

That shows how changing the operation from intersection to union changes the answer.

Tags: intersection, complement, universal set

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