Question

-3x^{2/3}

Original question: -3x^{2/3} ; ³\sqrt{-3x^2}; ³\sqrt{-3x^2}=; ³\sqrt{9x^2} -3x^{2/3}=; ³\sqrt{(3x)^2}=; ³\sqrt{-3x^2}=; ³\sqrt{9x^2}

Expert Verified Solution

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Expert intro: This is a direct rational-exponent conversion. The exponent 2/32/3 means cube root of the square, and the coefficient stays outside.

Detailed walkthrough

Use the rule

x2/3=x23x^{2/3}=\sqrt[3]{x^2}

So

3x2/3=3x23-3x^{2/3}=-3\sqrt[3]{x^2}

That is the correct radical form:

3x23\boxed{-3\sqrt[3]{x^2}}

You can also verify that this keeps the value unchanged for real xx.

💡 Pitfall guide

Do not rewrite it as 3x23\sqrt[3]{-3x^2} unless the original expression is exactly inside the radical. Also, do not change the exponent 2/32/3 into a square root; the denominator 3 means cube root.

🔄 Real-world variant

If the coefficient were positive, 3x2/3=3x233x^{2/3}=3\sqrt[3]{x^2}. If the exponent were 1/31/3, then the expression would be 3x3-3\sqrt[3]{x}.

🔍 Related terms

cube root, fractional exponent, coefficient

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