Question
How to solve a rational equation with like denominators
Original question: [?] 4 - \frac{3x}{x-9} + \frac{5x+72}{x-9} = -4 - \frac{3x}{x-9} = \frac{5x+72}{x-9} - 4 - \frac{3x}{x-9} - \frac{5x+72}{x-9} = -4 \frac{-3x-5x-72}{x-9} = -4 \frac{-8x-72}{x-9} = -4 \frac{5x+72}{x-9} = -4 - \frac{5x+72}{x-9} = -4 - \frac{5x(x-9)}{x-9} = -4
Expert Verified Solution
Key concept: When both fractions share the same denominator, it can feel like the problem should collapse fast. It does — but only if you keep the denominator restriction in mind while simplifying.
Step by step
Start by writing the equation clearly
The equation is intended to compare rational expressions with denominator .
A useful move is to combine everything on one side, then clear the denominator.
Step 1: Bring terms together
After moving terms, the work should lead to a single fraction over .
Step 2: Combine the numerators
When the fractions have the same denominator, you can combine them directly:
Step 3: Compare with the right side
If this equals , then multiply both sides by :
Expand the right side:
Step 4: Solve
Add to both sides:
Subtract 36:
So
Step 5: Check the restriction
Since , the only forbidden value is
So is valid.
Final answer
Pitfall alert
A lot of errors come from combining fractions too aggressively. Keep the numerator signs straight: is not the same as . That sign slip changes the whole answer.
Try different conditions
If the right side were a different constant, the same strategy still works: combine the fractions, clear the denominator, and solve the resulting linear equation. If the algebra produced , that would still be invalid because the denominator would vanish.
Further reading
common denominator, linear rational equation, domain check
FAQ
Can I add or subtract fractions with the same denominator directly?
Yes. Keep the denominator and combine the numerators, then simplify carefully.
What is the most important restriction in this type of problem?
Any value that makes the denominator zero must be excluded from the solution set.