Question

What happens to $y=\frac{1}{x}$ as $x$ goes to negative infinity?

Original question: (iii) $y=\frac{1}{x}$ as $x\to -\infty$. Solution $y\to 0$ Specific behaviours āœ“ describes correct behaviour (1 mark)

Expert Verified Solution

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Key takeaway: This is a small but important end-behavior question. For reciprocal functions, the sign of xx matters, but the limit idea is the same: as the input grows in magnitude, the output shrinks toward zero.

For

y=1x,y=\frac{1}{x},

as xā†’āˆ’āˆžx\to -\infty, the denominator becomes a very large negative number.

So the fraction gets closer and closer to 00 from the negative side:

  • when x=āˆ’10x=-10, y=āˆ’0.1y=-0.1
  • when x=āˆ’100x=-100, y=āˆ’0.01y=-0.01
  • when x=āˆ’1000x=-1000, y=āˆ’0.001y=-0.001

Therefore,

y→0.y\to 0.

If you want the signed behavior more precisely, you can say y→0āˆ’y\to 0^-, but many mark schemes accept simply 00.


Pitfalls the pros know šŸ‘‡ A common mistake is to write yā†’āˆžy\to\infty just because xā†’āˆ’āˆžx\to-\infty. For reciprocal functions, bigger ∣x∣|x| means smaller ∣1/x∣|1/x|. Another slip is forgetting the sign: here the values stay negative, even though they get very close to zero.

What if the problem changes? If the question were y=1xy=\frac{1}{x} as xā†’āˆžx\to\infty, the result would still be y→0y\to 0, but now from the positive side. If it were y=āˆ’1xy=-\frac{1}{x} as xā†’āˆ’āˆžx\to-\infty, then the values would approach 00 from the positive side instead.

Tags: end behavior, reciprocal function, limit at infinity

FAQ

What happens to $y=\frac{1}{x}$ as $x\to-\infty$?

As $x$ becomes a very large negative number, $\frac{1}{x}$ gets closer and closer to $0$. More precisely, it approaches $0$ from the negative side.

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