A 95% t-interval has the form x-bar ± t* (s/sqrt(n)). For n = 25, s = 10, x-bar = 50, t* = 2.064.
What is the margin of error?
- A
0.83
- Bcheck_circle
4.13
- C
20.64
- D
2.06
Explanation
ME = 2.064 * (10/sqrt(25)) = 2.064 * 2 = 4.13.
AP Statistics· difficulty 1/5
A 95% t-interval has the form x-bar ± t* (s/sqrt(n)). For n = 25, s = 10, x-bar = 50, t* = 2.064.
What is the margin of error?
0.83
4.13
20.64
2.06
Explanation
ME = 2.064 * (10/sqrt(25)) = 2.064 * 2 = 4.13.
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