Test scores are normal with mu = 75, sigma = 10. Find P(X < 60).
What approximate probability?
- A
≈ 0.5000
- B
≈ 0.9332
- Ccheck_circle
≈ 0.0668
- D
≈ 0.1587
Explanation
z = (60-75)/10 = -1.5. P(Z < -1.5) ≈ 0.0668.
The Normal Distribution
AP Statistics· difficulty 3/5
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