A binomial situation has p = 0.4 success and n = 6 trials.
What is the probability of exactly 3 successes?
- A
≈ 0.1500
- B
≈ 0.5000
- C
≈ 0.0640
- Dcheck_circle
≈ 0.2765
Explanation
C(6,3)(0.4)^3(0.6)^3 = 20(0.064)(0.216) = 0.27648.
AP Statistics· difficulty 4/5
A binomial situation has p = 0.4 success and n = 6 trials.
What is the probability of exactly 3 successes?
≈ 0.1500
≈ 0.5000
≈ 0.0640
≈ 0.2765
Explanation
C(6,3)(0.4)^3(0.6)^3 = 20(0.064)(0.216) = 0.27648.
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