Conditional Probability

AP Statistics· difficulty 4/5

A disease has prevalence 1%. Test sensitivity is 95%, false positive rate is 10%.

0.01 D 0.99 D^c + 0.95 - 0.05 + 0.10 - 0.90

Given a positive test, what is the probability of disease?

  • A

    0.01

  • B

    0.0876

    check_circle
  • C

    0.95

  • D

    0.50

Explanation

P(D|+) = 0.01(0.95)/[0.01(0.95) + 0.99(0.10)] = 0.0095/0.1085 ≈ 0.0876.

Want 10 more like this — adaptive to your weak spots?

Related questions