For X with P(0)=0.2, P(1)=0.5, P(2)=0.3, mu = 1.1.
What is Var(X)?
- A
0.70
- B
1.10
- Ccheck_circle
0.49
- D
0.30
Explanation
Var(X) = (0-1.1)^2(0.2) + (1-1.1)^2(0.5) + (2-1.1)^2(0.3) = 0.242 + 0.005 + 0.243 = 0.49.
Mean and Standard Deviation of Random Variables
AP Statistics· difficulty 4/5
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