A linear model fits log(y-hat) = 1 + 0.30 x (log base 10).
Predict y at x = 2.
- Acheck_circle
10^1.6 ~= 39.8
- B
10 + 0.6
- C
1.6
- D
0.30 * 2
Explanation
log(y-hat) = 1 + 0.30(2) = 1.6, so y-hat = 10^1.6 ~= 39.8.
AP Statistics· difficulty 3/5
A linear model fits log(y-hat) = 1 + 0.30 x (log base 10).
Predict y at x = 2.
10^1.6 ~= 39.8
10 + 0.6
1.6
0.30 * 2
Explanation
log(y-hat) = 1 + 0.30(2) = 1.6, so y-hat = 10^1.6 ~= 39.8.
Want 10 more like this — adaptive to your weak spots?