A standardized test has mean μ = 500 and standard deviation σ = 100. A student scored 650.
What is the z-score for this student's test score?
- A
150
- Bcheck_circle
1.5
- C
0.65
- D
−1.5
Explanation
z = (650 − 500)/100 = 150/100 = 1.5. The student is 1.5 standard deviations above the mean.