With b = 2, SE(b) = 0.4, n = 20 (df = 18, t* ≈ 2.101), 95% CI for β is
- A
(1.6, 2.4)
- Bcheck_circle
(1.16, 2.84)
- C
(2 − 0.84, 2 + 0.84)
- D
(0.0, 4.0)
Explanation
ME = 2.101·0.4 ≈ 0.84; CI = (1.16, 2.84).
AP Statistics· difficulty 4/5
With b = 2, SE(b) = 0.4, n = 20 (df = 18, t* ≈ 2.101), 95% CI for β is
(1.6, 2.4)
(1.16, 2.84)
(2 − 0.84, 2 + 0.84)
(0.0, 4.0)
Explanation
ME = 2.101·0.4 ≈ 0.84; CI = (1.16, 2.84).
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