SD of p̂₁ − p̂₂ for independent samples is
- A
Cannot be computed
- B
p₁(1−p₁) + p₂(1−p₂)
- Ccheck_circle
√(p₁(1−p₁)/n₁ + p₂(1−p₂)/n₂)
- D
(p₁ − p₂)/√n
Explanation
Variances of p̂s add; SD is the square root.
AP Statistics· difficulty 4/5
SD of p̂₁ − p̂₂ for independent samples is
Cannot be computed
p₁(1−p₁) + p₂(1−p₂)
√(p₁(1−p₁)/n₁ + p₂(1−p₂)/n₂)
(p₁ − p₂)/√n
Explanation
Variances of p̂s add; SD is the square root.
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