SD of p̂ from SRS of size n is
- A
p(1−p)/n
- Bcheck_circle
√(p(1−p)/n)
- C
√(p(1−p))
- D
n·p
Explanation
σ_p̂ = √(p(1−p)/n).
AP Statistics· difficulty 3/5
SD of p̂ from SRS of size n is
p(1−p)/n
√(p(1−p)/n)
√(p(1−p))
n·p
Explanation
σ_p̂ = √(p(1−p)/n).
Want 10 more like this — adaptive to your weak spots?