The 90th percentile of a standard normal is approximately z =
- A
1.65
- B
1.04
- Ccheck_circle
1.28
- D
2.33
Explanation
invNorm(0.90) ≈ 1.282.
The Normal Distribution
AP Statistics· difficulty 4/5
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AP Statistics· difficulty 4/5
The 90th percentile of a standard normal is approximately z =
1.65
1.04
1.28
2.33
Explanation
invNorm(0.90) ≈ 1.282.
Want 10 more like this — adaptive to your weak spots?