If sinθ=14\sin\theta=\frac{1}{4}sinθ=41 and θ\thetaθ is acute, what is tanθ\tan\thetatanθ?A15\sqrt{15}15B154\frac{\sqrt{15}}{4}415C117\frac{1}{\sqrt{17}}171D115\frac{1}{\sqrt{15}}151check_circleExplanationcosθ=154\cos\theta=\frac{\sqrt{15}}{4}cosθ=415. tanθ=1/415/4=115\tan\theta=\frac{1/4}{\sqrt{15}/4}=\frac{1}{\sqrt{15}}tanθ=15/41/4=151.