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Right Triangles and Trigonometry

SAT Math· difficulty 2/5

In right triangle ABCABC with right angle at CC, AB=10AB=10 and BC=6BC=6. What is sin⁡A\sin A?

  • A

    35\frac{3}{5}

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  • B

    34\frac{3}{4}

  • C

    53\frac{5}{3}

  • D

    45\frac{4}{5}

Explanation

AC=100−36=8AC=\sqrt{100-36}=8. sin⁡A=BCAB=610=35\sin A=\frac{BC}{AB}=\frac{6}{10}=\frac{3}{5}.

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