school
Acemy

Lines, Angles, and Triangles

SAT Math· difficulty 5/5

In triangle ABC, angle A = 90°90°, BC = 20, and sinB=frac35\\sin B = \\frac{3}{5}. What is the length of AC?

  • A

    300\sqrt{300}

  • B

    16

  • C

    12

    check_circle
  • D

    605\frac{60}{5}

Explanation

sinB=fractextoppositetexthypotenuse=fracACBC\\sin B = \\frac{\\text{opposite}}{\\text{hypotenuse}} = \\frac{AC}{BC}. So AC=20cdotfrac35=12AC = 20 \\cdot \\frac{3}{5} = 12.

Want 10 more like this — adaptive to your weak spots?

Practice 10 like thisarrow_forwardPredict my AP score

Related questions

auto_awesomeAll Toolsquestion_answerHomework Q&Amenu_bookAP & SAT PreptimelineLearn Mode