Lines, Angles, and Triangles

SAT Math· difficulty 4/5

In triangle ABC, point D is on AB and point E is on AC such that DE is parallel to BC. If AD = 4, DB = 6, and BC = 15, what is the length of DE?

  • A

    152\frac{15}{2}

  • B

    10

  • C

    9

  • D

    6

    check_circle

Explanation

Triangle ADE ~ triangle ABC. Ratio: fracADAB=frac410=frac25\\frac{AD}{AB} = \\frac{4}{10} = \\frac{2}{5}. So DE=frac25(15)=6DE = \\frac{2}{5}(15) = 6.

Want 10 more like this — adaptive to your weak spots?

Related questions