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Linear Functions

SAT Math· difficulty 3/5

A car worth \24{,}000depreciatesdepreciates$1{,}500peryear.Itsvalueper year. Its valueVafteraftert$ years is:

  • A

    V=24000−1500tV = 24000 - 1500t

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  • B

    V=24000+1500tV = 24000 + 1500t

  • C

    V=24000(1500)tV = 24000(1500)t

  • D

    V=1500−24000tV = 1500 - 24000t

Explanation

Start at 24,00024{,}000 and decrease by 15001500 each year.

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