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Linear Functions

SAT Math· difficulty 5/5

For f(x)=mx+bf(x) = mx + b, the points (2,f(2))(2, f(2)) and (7,f(7))(7, f(7)) are reflected across y=xy = x. The new points lie on y=y =:

  • A

    f−1(x)f^{-1}(x)

  • B

    All of the above

    check_circle
  • C

    1m(x−b)\dfrac{1}{m}(x - b)

  • D

    x−bm\dfrac{x - b}{m}

Explanation

Reflecting across y=xy = x produces the inverse: f−1(x)=(x−b)/mf^{-1}(x) = (x - b)/m.

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