For what value of bbb does f(x)=3x+bf(x) = 3x + bf(x)=3x+b have f−1(2)=−1f^{-1}(2) = -1f−1(2)=−1?A555check_circleB−5-5−5C−2-2−2D222Explanationf−1(2)=−1 ⟺ f(−1)=2f^{-1}(2) = -1 \iff f(-1) = 2f−1(2)=−1⟺f(−1)=2. So −3+b=2⇒b=5-3 + b = 2 \Rightarrow b = 5−3+b=2⇒b=5.