If f(x)=2x+1f(x) = 2x + 1f(x)=2x+1 and g(x)=x−12g(x) = \dfrac{x - 1}{2}g(x)=2x−1, then f(g(x))f(g(x))f(g(x)) equalsAxxxcheck_circleB2x2x2xCx+1x + 1x+1Dx−12+1\dfrac{x-1}{2} + 12x−1+1Explanationggg is the inverse of fff, so f(g(x))=xf(g(x)) = xf(g(x))=x. Verification: f(g(x))=2⋅x−12+1=xf(g(x)) = 2 \cdot \frac{x-1}{2} + 1 = xf(g(x))=2⋅2x−1+1=x.