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Linear Inequalities in One or Two Variables

SAT Math· difficulty 4/5

What is the solution to 2x−13≤x+24\frac{2x - 1}{3} \leq \frac{x + 2}{4}?

  • A

    x≥2x \geq 2

  • B

    x≤−2x \leq -2

  • C

    x≥−2x \geq -2

  • D

    x≤2x \leq 2

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Explanation

Multiply by 12: 4(2x−1)≤3(x+2)4(2x - 1) \leq 3(x + 2). So 8x−4≤3x+68x - 4 \leq 3x + 6, giving 5x≤105x \leq 10 and x≤2x \leq 2.

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