Which is equivalent to 11−1x\frac{1}{1 - \frac{1}{x}}1−x11?Axx−1\frac{x}{x - 1}x−1xcheck_circleBx−1x - 1x−1Cx−1x\frac{x - 1}{x}xx−1D1x−1\frac{1}{x - 1}x−11Explanation1−1x=x−1x1 - \frac{1}{x} = \frac{x - 1}{x}1−x1=xx−1, so 1(x−1)/x=xx−1\frac{1}{(x-1)/x} = \frac{x}{x - 1}(x−1)/x1=x−1x.