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Nonlinear Functions

SAT Math· difficulty 4/5

Which equation has a vertical asymptote at x=−1x = -1?

  • A

    y=2x+1y = \frac{2}{x + 1}

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  • B

    y=xx2+1y = \frac{x}{x^2 + 1}

  • C

    y=x+1x−1y = \frac{x + 1}{x - 1}

  • D

    y=2x−1y = \frac{2}{x - 1}

Explanation

Vertical asymptote at x=−1x = -1 requires the denominator to be zero there: x+1=0x + 1 = 0.

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