Nonlinear Functions

SAT Math· difficulty 5/5

The graph of ff passes through (3,8)(3, 8) and (7,1)(7, -1). The graph of f1f^{-1} must pass through:

  • A

    (3,8)(3, 8) and (7,1)(7, -1)

  • B

    (8,3)(8, 3) and (1,7)(-1, 7)

    check_circle
  • C

    (8,7)(8, 7) and (1,3)(-1, 3)

  • D

    (3,8)(-3, -8) and (7,1)(-7, 1)

Explanation

The inverse swaps xx and yy coordinates: (3,8)(8,3)(3, 8) \to (8, 3) and (7,1)(1,7)(7, -1) \to (-1, 7).

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