Nonlinear Functions

SAT Math· difficulty 5/5

If f(x)=xx1f(x) = \frac{x}{x - 1}, what is f1(x)f^{-1}(x)?

  • A

    1xx\frac{1 - x}{x}

  • B

    xx1\frac{x}{x - 1}

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  • C

    x1x\frac{x - 1}{x}

  • D

    x+1x\frac{x + 1}{x}

Explanation

y=xx1y(x1)=xyxy=xx(y1)=yx=yy1y = \frac{x}{x - 1} \Rightarrow y(x - 1) = x \Rightarrow yx - y = x \Rightarrow x(y - 1) = y \Rightarrow x = \frac{y}{y - 1}. So f1(x)=xx1f^{-1}(x) = \frac{x}{x - 1}ff is its own inverse.

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