Which is a factor of x3−7x−6x^3 - 7x - 6x3−7x−6?Ax+6x + 6x+6Bx+1x + 1x+1check_circleCx−7x - 7x−7Dx−1x - 1x−1ExplanationTest x=−1x = -1x=−1: (−1)3−7(−1)−6=−1+7−6=0(-1)^3 - 7(-1) - 6 = -1 + 7 - 6 = 0(−1)3−7(−1)−6=−1+7−6=0. So x+1x + 1x+1 is a factor.