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Nonlinear Functions

SAT Math· difficulty 4/5

The function hh is defined by h(x)=2(x+1)2−5h(x) = 2(x + 1)^2 - 5. The vertex of its graph is at:

  • A

    (−1,5)(-1, 5)

  • B

    (1,−5)(1, -5)

  • C

    (1,5)(1, 5)

  • D

    (−1,−5)(-1, -5)

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Explanation

For a(x−h)2+ka(x - h)^2 + k, the vertex is (h,k)(h, k). Here h=−1,k=−5h = -1, k = -5, so vertex is (−1,−5)(-1, -5).

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