Which expression is equivalent to y=−3(x−1)2+7y = -3(x - 1)^2 + 7y=−3(x−1)2+7?Ay=−3x2+6x+7y = -3x^2 + 6x + 7y=−3x2+6x+7By=−3x2+6x+10y = -3x^2 + 6x + 10y=−3x2+6x+10Cy=−3x2+6x+4y = -3x^2 + 6x + 4y=−3x2+6x+4check_circleDy=−3x2−6x+4y = -3x^2 - 6x + 4y=−3x2−6x+4Explanation−3(x−1)2+7=−3(x2−2x+1)+7=−3x2+6x−3+7=−3x2+6x+4-3(x - 1)^2 + 7 = -3(x^2 - 2x + 1) + 7 = -3x^2 + 6x - 3 + 7 = -3x^2 + 6x + 4−3(x−1)2+7=−3(x2−2x+1)+7=−3x2+6x−3+7=−3x2+6x+4.