Which is equivalent to x2−4x+4x−2\frac{x^2 - 4x + 4}{x - 2}x−2x2−4x+4 (for x≠2x \neq 2x=2)?A1x−2\frac{1}{x - 2}x−21Bx+2x + 2x+2Cx2−2x^2 - 2x2−2Dx−2x - 2x−2check_circleExplanationx2−4x+4=(x−2)2x^2 - 4x + 4 = (x - 2)^2x2−4x+4=(x−2)2, so (x−2)2x−2=x−2\frac{(x - 2)^2}{x - 2} = x - 2x−2(x−2)2=x−2.