Which is equivalent to x6⋅x−2x3\frac{x^6 \cdot x^{-2}}{x^3}x3x6⋅x−2?Ax2x^2x2Bx−1x^{-1}x−1Cx3x^3x3Dxxxcheck_circleExplanationx6+(−2)x3=x4x3=x4−3=x\frac{x^{6 + (-2)}}{x^3} = \frac{x^4}{x^3} = x^{4 - 3} = xx3x6+(−2)=x3x4=x4−3=x.