Which is equivalent to 1x+1x+1\frac{1}{x} + \frac{1}{x + 1}x1+x+11?Ax+1x(x+1)\frac{x + 1}{x(x + 1)}x(x+1)x+1B2xx(x+1)\frac{2x}{x(x + 1)}x(x+1)2xC22x+1\frac{2}{2x + 1}2x+12D2x+1x(x+1)\frac{2x + 1}{x(x + 1)}x(x+1)2x+1check_circleExplanationCommon denominator: (x+1)+xx(x+1)=2x+1x(x+1)\frac{(x + 1) + x}{x(x + 1)} = \frac{2x + 1}{x(x + 1)}x(x+1)(x+1)+x=x(x+1)2x+1.