What is the horizontal asymptote of y=3⋅2x−1−5y = 3 \cdot 2^{x - 1} - 5y=3⋅2x−1−5?Ay=3y = 3y=3By=−5y = -5y=−5check_circleCy=−1y = -1y=−1Dy=0y = 0y=0ExplanationAs x→−∞x \to -\inftyx→−∞, 2x−1→02^{x-1} \to 02x−1→0, so y→0−5=−5y \to 0 - 5 = -5y→0−5=−5.