Which is equivalent to x2−9x2−6x+9\frac{x^2 - 9}{x^2 - 6x + 9}x2−6x+9x2−9?Ax−3x+3\frac{x - 3}{x + 3}x+3x−3Bx+3x + 3x+3Cx+3x−3\frac{x + 3}{x - 3}x−3x+3check_circleD1x−3\frac{1}{x - 3}x−31Explanation(x−3)(x+3)(x−3)2=x+3x−3\frac{(x - 3)(x + 3)}{(x - 3)^2} = \frac{x + 3}{x - 3}(x−3)2(x−3)(x+3)=x−3x+3 (for x≠3x \neq 3x=3).