If f(x)=x2−1f(x) = x^2 - 1f(x)=x2−1 and g(x)=x+2g(x) = x + 2g(x)=x+2, what is g(f(x))g(f(x))g(f(x))?A(x+2)2−1(x + 2)^2 - 1(x+2)2−1Bx2−1x^2 - 1x2−1Cx2+2x^2 + 2x2+2Dx2+1x^2 + 1x2+1check_circleExplanationg(f(x))=f(x)+2=(x2−1)+2=x2+1g(f(x)) = f(x) + 2 = (x^2 - 1) + 2 = x^2 + 1g(f(x))=f(x)+2=(x2−1)+2=x2+1.