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Nonlinear Functions

SAT Math· difficulty 3/5

For V(t)=8000⋅(0.92)tV(t) = 8000 \cdot (0.92)^t, the depreciation rate per year is:

  • A

    0.92%0.92\%

  • B

    9.2%9.2\%

  • C

    8%8\%

    check_circle
  • D

    92%92\%

Explanation

1−0.92=0.08=8%1 - 0.92 = 0.08 = 8\% per year decrease.

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