Simplify: a23⋅a6\sqrt[3]{a^2} \cdot \sqrt[6]{a}3a2⋅6a as a single power of aaa.Aa1/2a^{1/2}a1/2Ba2/3a^{2/3}a2/3Ca7/6a^{7/6}a7/6Da5/6a^{5/6}a5/6check_circleExplanationa2/3⋅a1/6=a4/6+1/6=a5/6a^{2/3} \cdot a^{1/6} = a^{4/6 + 1/6} = a^{5/6}a2/3⋅a1/6=a4/6+1/6=a5/6.