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Nonlinear Functions

SAT Math· difficulty 4/5

For h(t)=200(0.7)th(t) = 200(0.7)^t, tt in days, the half-life occurs nearest:

  • A

    t≈1.0t \approx 1.0 days

  • B

    t≈1.9t \approx 1.9 days

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  • C

    t≈2.5t \approx 2.5 days

  • D

    t≈1.5t \approx 1.5 days

Explanation

Solve 0.7t=0.50.7^t = 0.5: t=log⁡0.5/log⁡0.7≈−0.301/−0.155≈1.94t = \log 0.5 / \log 0.7 \approx -0.301/-0.155 \approx 1.94 days.

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